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X^2-40X-48000=0
a = 1; b = -40; c = -48000;
Δ = b2-4ac
Δ = -402-4·1·(-48000)
Δ = 193600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{193600}=440$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-40)-440}{2*1}=\frac{-400}{2} =-200 $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-40)+440}{2*1}=\frac{480}{2} =240 $
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